Most programming languages offer various bit level manipulation operators (bitwise and, bitwise or, shifting to the right or to the left, etc.).
Puzzles like this one are a great way to learn about the bit level representation of numbers and the various bit related operators.
This puzzle requires you to implement a piece of code with only a limited set of operators.
Your solution to the puzzles gets validated automatically and your score is based on the total length of your code (lower score is better).
Return true iff x contains exactly one bit set to 1
˜ & ^ | + << >> >>>
Your solution can only use assignments and the above list of operators. You cannot use any
if) statements, or loops (no
You can assign intermediate results to as many variables as you need (assignments don't count towards your score) and you can use constants in the 0-255 range.
Go ahead, and write your code below. Hit validate when you are done!
Aug 31, 2016: Tom Theisen for sending me a better solution.
Jun 29, 2019: Royce Rajan crushed the previous best solution!
Here is some information on what each operator does:
|Flips all the bits in x.|
|For each bit in x,y, sets the result's bit to 1 if both x and y have their bit set.|
|For each bit in x,y, sets the result's bit to 1 if x or y, but not both, have their bit set.|
|For each bit in x,y, sets the result's bit to 1 if x or y have their bit set.|
|Adds x and y.|
|Shifts the bits in x to the left, by n bits.|
|Shifts the bits in x to the right, by n bits. The sign is maintained.|
|Shifts the bits in x to the right, by n bits. Zeros are filled in from the left.|
Note: A useful trick is
-x = ~x+1!
More similar puzzles:
And a rich collection of hacks:
Sometimes you use this kind of trick in production code.